Integrand size = 16, antiderivative size = 16 \[ \int \frac {\sin \left (a+b x-c x^2\right )}{x} \, dx=\text {Int}\left (\frac {\sin \left (a+b x-c x^2\right )}{x},x\right ) \]
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Not integrable
Time = 0.01 (sec) , antiderivative size = 16, normalized size of antiderivative = 1.00, number of steps used = 0, number of rules used = 0, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.000, Rules used = {} \[ \int \frac {\sin \left (a+b x-c x^2\right )}{x} \, dx=\int \frac {\sin \left (a+b x-c x^2\right )}{x} \, dx \]
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Rubi steps \begin{align*} \text {integral}& = \int \frac {\sin \left (a+b x-c x^2\right )}{x} \, dx \\ \end{align*}
Not integrable
Time = 2.89 (sec) , antiderivative size = 18, normalized size of antiderivative = 1.12 \[ \int \frac {\sin \left (a+b x-c x^2\right )}{x} \, dx=\int \frac {\sin \left (a+b x-c x^2\right )}{x} \, dx \]
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Not integrable
Time = 0.12 (sec) , antiderivative size = 16, normalized size of antiderivative = 1.00
\[\int \frac {\sin \left (-c \,x^{2}+b x +a \right )}{x}d x\]
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Not integrable
Time = 0.34 (sec) , antiderivative size = 21, normalized size of antiderivative = 1.31 \[ \int \frac {\sin \left (a+b x-c x^2\right )}{x} \, dx=\int { \frac {\sin \left (-c x^{2} + b x + a\right )}{x} \,d x } \]
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Not integrable
Time = 0.37 (sec) , antiderivative size = 14, normalized size of antiderivative = 0.88 \[ \int \frac {\sin \left (a+b x-c x^2\right )}{x} \, dx=\int \frac {\sin {\left (a + b x - c x^{2} \right )}}{x}\, dx \]
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Not integrable
Time = 0.35 (sec) , antiderivative size = 22, normalized size of antiderivative = 1.38 \[ \int \frac {\sin \left (a+b x-c x^2\right )}{x} \, dx=\int { \frac {\sin \left (-c x^{2} + b x + a\right )}{x} \,d x } \]
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Not integrable
Time = 0.31 (sec) , antiderivative size = 18, normalized size of antiderivative = 1.12 \[ \int \frac {\sin \left (a+b x-c x^2\right )}{x} \, dx=\int { \frac {\sin \left (-c x^{2} + b x + a\right )}{x} \,d x } \]
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Not integrable
Time = 5.75 (sec) , antiderivative size = 18, normalized size of antiderivative = 1.12 \[ \int \frac {\sin \left (a+b x-c x^2\right )}{x} \, dx=\int \frac {\sin \left (-c\,x^2+b\,x+a\right )}{x} \,d x \]
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